x^2-730x+40200=0

Solution for x^2-730x+40200=0 equation:

x^2-730x+40200=0

a = 1; b = -730; c = +40200;
Δ = b2-4ac
Δ = -7302-4·1·40200
Δ = 372100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{372100}=610$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-730)-610}{2*1}=\frac{120}{2}
=60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-730)+610}{2*1}=\frac{1340}{2}
=670
$